-3(2s-4)-12=3(7s+1)-4

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Solution for -3(2s-4)-12=3(7s+1)-4 equation: 



-3(2s-4)-12=3(7s+1)-4

We move all terms to the left:

-3(2s-4)-12-(3(7s+1)-4)=0

We multiply parentheses

-6s-(3(7s+1)-4)+12-12=0



We calculate terms in parentheses: -(3(7s+1)-4), so:

3(7s+1)-4

We multiply parentheses

21s+3-4

We add all the numbers together, and all the variables

21s-1

Back to the equation:

-(21s-1)



We add all the numbers together, and all the variables

-6s-(21s-1)=0

We get rid of parentheses

-6s-21s+1=0

We add all the numbers together, and all the variables

-27s+1=0

We move all terms containing s to the left, all other terms to the right

-27s=-1

s=-1/-27

s=1/27

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