-3(2s-5)-15=-3(9s+2)-3

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Solution for -3(2s-5)-15=-3(9s+2)-3 equation: 



-3(2s-5)-15=-3(9s+2)-3

We move all terms to the left:

-3(2s-5)-15-(-3(9s+2)-3)=0

We multiply parentheses

-6s-(-3(9s+2)-3)+15-15=0



We calculate terms in parentheses: -(-3(9s+2)-3), so:

-3(9s+2)-3

We multiply parentheses

-27s-6-3

We add all the numbers together, and all the variables

-27s-9

Back to the equation:

-(-27s-9)



We add all the numbers together, and all the variables

-6s-(-27s-9)=0

We get rid of parentheses

-6s+27s+9=0

We add all the numbers together, and all the variables

21s+9=0

We move all terms containing s to the left, all other terms to the right

21s=-9

s=-9/21

s=-3/7

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