-3(2s-6)+7(s-10)=-52-10

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Solution for -3(2s-6)+7(s-10)=-52-10 equation: 



-3(2s-6)+7(s-10)=-52-10

We move all terms to the left:

-3(2s-6)+7(s-10)-(-52-10)=0

We add all the numbers together, and all the variables

-3(2s-6)+7(s-10)-(-62)=0

We add all the numbers together, and all the variables

-3(2s-6)+7(s-10)+62=0

We multiply parentheses

-6s+7s+18-70+62=0

We add all the numbers together, and all the variables

s+10=0

We move all terms containing s to the left, all other terms to the right

s=-10

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