-3(2t+1)+2t=2(t+9)+3

Solution for -3(2t+1)+2t=2(t+9)+3 equation:

-3(2t+1)+2t=2(t+9)+3

We move all terms to the left:

-3(2t+1)+2t-(2(t+9)+3)=0

We add all the numbers together, and all the variables

2t-3(2t+1)-(2(t+9)+3)=0

We multiply parentheses

2t-6t-(2(t+9)+3)-3=0


We calculate terms in parentheses: -(2(t+9)+3), so:

2(t+9)+3

We multiply parentheses

2t+18+3

We add all the numbers together, and all the variables

2t+21

Back to the equation:

-(2t+21)


We add all the numbers together, and all the variables

-4t-(2t+21)-3=0

We get rid of parentheses

-4t-2t-21-3=0

We add all the numbers together, and all the variables

-6t-24=0

We move all terms containing t to the left, all other terms to the right

-6t=24

t=24/-6

t=-4