-3(2t+1)+2t=2(t-9)+3

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Solution for -3(2t+1)+2t=2(t-9)+3 equation: 



-3(2t+1)+2t=2(t-9)+3

We move all terms to the left:

-3(2t+1)+2t-(2(t-9)+3)=0

We add all the numbers together, and all the variables

2t-3(2t+1)-(2(t-9)+3)=0

We multiply parentheses

2t-6t-(2(t-9)+3)-3=0



We calculate terms in parentheses: -(2(t-9)+3), so:

2(t-9)+3

We multiply parentheses

2t-18+3

We add all the numbers together, and all the variables

2t-15

Back to the equation:

-(2t-15)



We add all the numbers together, and all the variables

-4t-(2t-15)-3=0

We get rid of parentheses

-4t-2t+15-3=0

We add all the numbers together, and all the variables

-6t+12=0

We move all terms containing t to the left, all other terms to the right

-6t=-12

t=-12/-6

t=+2

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