-3(2t+10)=-48

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Solution for -3(2t+10)=-48 equation: 



-3(2t+10)=-48

We move all terms to the left:

-3(2t+10)-(-48)=0

We add all the numbers together, and all the variables

-3(2t+10)+48=0

We multiply parentheses

-6t-30+48=0

We add all the numbers together, and all the variables

-6t+18=0

We move all terms containing t to the left, all other terms to the right

-6t=-18

t=-18/-6

t=+3

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