-3(2t-1)=t+t+3

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Solution for -3(2t-1)=t+t+3 equation: 



-3(2t-1)=t+t+3

We move all terms to the left:

-3(2t-1)-(t+t+3)=0

We add all the numbers together, and all the variables

-3(2t-1)-(2t+3)=0

We multiply parentheses

-6t-(2t+3)+3=0

We get rid of parentheses

-6t-2t-3+3=0

We add all the numbers together, and all the variables

-8t=0

t=0/-8

t=0

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