-3(2t-1)=t+t+t+t+3

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Solution for -3(2t-1)=t+t+t+t+3 equation: 



-3(2t-1)=t+t+t+t+3

We move all terms to the left:

-3(2t-1)-(t+t+t+t+3)=0

We add all the numbers together, and all the variables

-3(2t-1)-(4t+3)=0

We multiply parentheses

-6t-(4t+3)+3=0

We get rid of parentheses

-6t-4t-3+3=0

We add all the numbers together, and all the variables

-10t=0

t=0/-10

t=0

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