-3(2t-2)+2t=3t-5

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Solution for -3(2t-2)+2t=3t-5 equation: 



-3(2t-2)+2t=3t-5

We move all terms to the left:

-3(2t-2)+2t-(3t-5)=0

We add all the numbers together, and all the variables

2t-3(2t-2)-(3t-5)=0

We multiply parentheses

2t-6t-(3t-5)+6=0

We get rid of parentheses

2t-6t-3t+5+6=0

We add all the numbers together, and all the variables

-7t+11=0

We move all terms containing t to the left, all other terms to the right

-7t=-11

t=-11/-7

t=1+4/7

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