-3(2t-3)+2t=3t-6

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Solution for -3(2t-3)+2t=3t-6 equation: 



-3(2t-3)+2t=3t-6

We move all terms to the left:

-3(2t-3)+2t-(3t-6)=0

We add all the numbers together, and all the variables

2t-3(2t-3)-(3t-6)=0

We multiply parentheses

2t-6t-(3t-6)+9=0

We get rid of parentheses

2t-6t-3t+6+9=0

We add all the numbers together, and all the variables

-7t+15=0

We move all terms containing t to the left, all other terms to the right

-7t=-15

t=-15/-7

t=2+1/7

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