-3(2t-5)+2t=6t-8

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Solution for -3(2t-5)+2t=6t-8 equation: 



-3(2t-5)+2t=6t-8

We move all terms to the left:

-3(2t-5)+2t-(6t-8)=0

We add all the numbers together, and all the variables

2t-3(2t-5)-(6t-8)=0

We multiply parentheses

2t-6t-(6t-8)+15=0

We get rid of parentheses

2t-6t-6t+8+15=0

We add all the numbers together, and all the variables

-10t+23=0

We move all terms containing t to the left, all other terms to the right

-10t=-23

t=-23/-10

t=2+3/10

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