-3(2t-5)+2t=6t-8

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Solution for -3(2t-5)+2t=6t-8 equation:



-3(2t-5)+2t=6t-8
We move all terms to the left:
-3(2t-5)+2t-(6t-8)=0
We add all the numbers together, and all the variables
2t-3(2t-5)-(6t-8)=0
We multiply parentheses
2t-6t-(6t-8)+15=0
We get rid of parentheses
2t-6t-6t+8+15=0
We add all the numbers together, and all the variables
-10t+23=0
We move all terms containing t to the left, all other terms to the right
-10t=-23
t=-23/-10
t=2+3/10

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