-3(2u-1)+4u=2+2(5u-1)

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Solution for -3(2u-1)+4u=2+2(5u-1) equation: 



-3(2u-1)+4u=2+2(5u-1)

We move all terms to the left:

-3(2u-1)+4u-(2+2(5u-1))=0

We add all the numbers together, and all the variables

4u-3(2u-1)-(2+2(5u-1))=0

We multiply parentheses

4u-6u-(2+2(5u-1))+3=0



We calculate terms in parentheses: -(2+2(5u-1)), so:

2+2(5u-1)

determiningTheFunctionDomain
2(5u-1)+2

We multiply parentheses

10u-2+2

We add all the numbers together, and all the variables

10u

Back to the equation:

-(10u)



We add all the numbers together, and all the variables

-12u+3=0

We move all terms containing u to the left, all other terms to the right

-12u=-3

u=-3/-12

u=1/4

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