-3(2u-1)+6u=9+4(2u-1)

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Solution for -3(2u-1)+6u=9+4(2u-1) equation: 



-3(2u-1)+6u=9+4(2u-1)

We move all terms to the left:

-3(2u-1)+6u-(9+4(2u-1))=0

We add all the numbers together, and all the variables

6u-3(2u-1)-(9+4(2u-1))=0

We multiply parentheses

6u-6u-(9+4(2u-1))+3=0



We calculate terms in parentheses: -(9+4(2u-1)), so:

9+4(2u-1)

determiningTheFunctionDomain
4(2u-1)+9

We multiply parentheses

8u-4+9

We add all the numbers together, and all the variables

8u+5

Back to the equation:

-(8u+5)



We add all the numbers together, and all the variables

-(8u+5)+3=0

We get rid of parentheses

-8u-5+3=0

We add all the numbers together, and all the variables

-8u-2=0

We move all terms containing u to the left, all other terms to the right

-8u=2

u=2/-8

u=-1/4

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