-3(2u-4)+7u=7(u+2)

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Solution for -3(2u-4)+7u=7(u+2) equation: 



-3(2u-4)+7u=7(u+2)

We move all terms to the left:

-3(2u-4)+7u-(7(u+2))=0

We add all the numbers together, and all the variables

7u-3(2u-4)-(7(u+2))=0

We multiply parentheses

7u-6u-(7(u+2))+12=0



We calculate terms in parentheses: -(7(u+2)), so:

7(u+2)

We multiply parentheses

7u+14

Back to the equation:

-(7u+14)



We add all the numbers together, and all the variables

u-(7u+14)+12=0

We get rid of parentheses

u-7u-14+12=0

We add all the numbers together, and all the variables

-6u-2=0

We move all terms containing u to the left, all other terms to the right

-6u=2

u=2/-6

u=-1/3

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