-3(2u-6)+2u=6(u+6)

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Solution for -3(2u-6)+2u=6(u+6) equation: 



-3(2u-6)+2u=6(u+6)

We move all terms to the left:

-3(2u-6)+2u-(6(u+6))=0

We add all the numbers together, and all the variables

2u-3(2u-6)-(6(u+6))=0

We multiply parentheses

2u-6u-(6(u+6))+18=0



We calculate terms in parentheses: -(6(u+6)), so:

6(u+6)

We multiply parentheses

6u+36

Back to the equation:

-(6u+36)



We add all the numbers together, and all the variables

-4u-(6u+36)+18=0

We get rid of parentheses

-4u-6u-36+18=0

We add all the numbers together, and all the variables

-10u-18=0

We move all terms containing u to the left, all other terms to the right

-10u=18

u=18/-10

u=-1+4/5

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