-3(2w+5)+7w=5(w-11)

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Solution for -3(2w+5)+7w=5(w-11) equation: 



-3(2w+5)+7w=5(w-11)

We move all terms to the left:

-3(2w+5)+7w-(5(w-11))=0

We add all the numbers together, and all the variables

7w-3(2w+5)-(5(w-11))=0

We multiply parentheses

7w-6w-(5(w-11))-15=0



We calculate terms in parentheses: -(5(w-11)), so:

5(w-11)

We multiply parentheses

5w-55

Back to the equation:

-(5w-55)



We add all the numbers together, and all the variables

w-(5w-55)-15=0

We get rid of parentheses

w-5w+55-15=0

We add all the numbers together, and all the variables

-4w+40=0

We move all terms containing w to the left, all other terms to the right

-4w=-40

w=-40/-4

w=+10

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