-3(2w+5)+7w=5(w-11)

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Solution for -3(2w+5)+7w=5(w-11) equation:



-3(2w+5)+7w=5(w-11)
We move all terms to the left:
-3(2w+5)+7w-(5(w-11))=0
We add all the numbers together, and all the variables
7w-3(2w+5)-(5(w-11))=0
We multiply parentheses
7w-6w-(5(w-11))-15=0
We calculate terms in parentheses: -(5(w-11)), so:
5(w-11)
We multiply parentheses
5w-55
Back to the equation:
-(5w-55)
We add all the numbers together, and all the variables
w-(5w-55)-15=0
We get rid of parentheses
w-5w+55-15=0
We add all the numbers together, and all the variables
-4w+40=0
We move all terms containing w to the left, all other terms to the right
-4w=-40
w=-40/-4
w=+10

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