-3(2w-5)+4w=1+2(3w-2)

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Solution for -3(2w-5)+4w=1+2(3w-2) equation: 



-3(2w-5)+4w=1+2(3w-2)

We move all terms to the left:

-3(2w-5)+4w-(1+2(3w-2))=0

We add all the numbers together, and all the variables

4w-3(2w-5)-(1+2(3w-2))=0

We multiply parentheses

4w-6w-(1+2(3w-2))+15=0



We calculate terms in parentheses: -(1+2(3w-2)), so:

1+2(3w-2)

determiningTheFunctionDomain
2(3w-2)+1

We multiply parentheses

6w-4+1

We add all the numbers together, and all the variables

6w-3

Back to the equation:

-(6w-3)



We add all the numbers together, and all the variables

-2w-(6w-3)+15=0

We get rid of parentheses

-2w-6w+3+15=0

We add all the numbers together, and all the variables

-8w+18=0

We move all terms containing w to the left, all other terms to the right

-8w=-18

w=-18/-8

w=2+1/4

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