-3(2x-3)+10x=38

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Solution for -3(2x-3)+10x=38 equation: 



-3(2x-3)+10x=38

We move all terms to the left:

-3(2x-3)+10x-(38)=0

We add all the numbers together, and all the variables

10x-3(2x-3)-38=0

We multiply parentheses

10x-6x+9-38=0

We add all the numbers together, and all the variables

4x-29=0

We move all terms containing x to the left, all other terms to the right

4x=29

x=29/4

x=7+1/4

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