-3(2x-3)=3(x+1)+10

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Solution for -3(2x-3)=3(x+1)+10 equation:



-3(2x-3)=3(x+1)+10
We move all terms to the left:
-3(2x-3)-(3(x+1)+10)=0
We multiply parentheses
-6x-(3(x+1)+10)+9=0
We calculate terms in parentheses: -(3(x+1)+10), so:
3(x+1)+10
We multiply parentheses
3x+3+10
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
We get rid of parentheses
-6x-3x-13+9=0
We add all the numbers together, and all the variables
-9x-4=0
We move all terms containing x to the left, all other terms to the right
-9x=4
x=4/-9
x=-4/9

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