-3(2x-3)=3(x+1)+10

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Solution for -3(2x-3)=3(x+1)+10 equation: 



-3(2x-3)=3(x+1)+10

We move all terms to the left:

-3(2x-3)-(3(x+1)+10)=0

We multiply parentheses

-6x-(3(x+1)+10)+9=0



We calculate terms in parentheses: -(3(x+1)+10), so:

3(x+1)+10

We multiply parentheses

3x+3+10

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

-6x-3x-13+9=0

We add all the numbers together, and all the variables

-9x-4=0

We move all terms containing x to the left, all other terms to the right

-9x=4

x=4/-9

x=-4/9

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