-3(2x-4)+5(3x+5)=64

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Solution for -3(2x-4)+5(3x+5)=64 equation: 



-3(2x-4)+5(3x+5)=64

We move all terms to the left:

-3(2x-4)+5(3x+5)-(64)=0

We multiply parentheses

-6x+15x+12+25-64=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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