-3(2x-4)=4(3/4x-3)

Solution for -3(2x-4)=4(3/4x-3) equation:

-3(2x-4)=4(3/4x-3)

We move all terms to the left:

-3(2x-4)-(4(3/4x-3))=0


Domain of the equation: 4x-3))!=0

x∈R


We multiply parentheses

-6x-(4(3/4x-3))+12=0

We multiply all the terms by the denominator


-6x*4x+12*4x-3))-(4(3-3))=0

We add all the numbers together, and all the variables

-6x*4x+12*4x-3))-(40)=0

We add all the numbers together, and all the variables

-6x*4x+12*4x=0

Wy multiply elements

-24x^2+48x=0

a = -24; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-24)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-24}=\frac{-96}{-48}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-24}=\frac{0}{-48}
=0
$