-3(2x-5)+3x=7+2(6x-5)

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Solution for -3(2x-5)+3x=7+2(6x-5) equation: 



-3(2x-5)+3x=7+2(6x-5)

We move all terms to the left:

-3(2x-5)+3x-(7+2(6x-5))=0

We add all the numbers together, and all the variables

3x-3(2x-5)-(7+2(6x-5))=0

We multiply parentheses

3x-6x-(7+2(6x-5))+15=0



We calculate terms in parentheses: -(7+2(6x-5)), so:

7+2(6x-5)

determiningTheFunctionDomain
2(6x-5)+7

We multiply parentheses

12x-10+7

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We add all the numbers together, and all the variables

-3x-(12x-3)+15=0

We get rid of parentheses

-3x-12x+3+15=0

We add all the numbers together, and all the variables

-15x+18=0

We move all terms containing x to the left, all other terms to the right

-15x=-18

x=-18/-15

x=1+1/5

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