-3(2x-5)=2(3x-3)+3

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Solution for -3(2x-5)=2(3x-3)+3 equation: 



-3(2x-5)=2(3x-3)+3

We move all terms to the left:

-3(2x-5)-(2(3x-3)+3)=0

We multiply parentheses

-6x-(2(3x-3)+3)+15=0



We calculate terms in parentheses: -(2(3x-3)+3), so:

2(3x-3)+3

We multiply parentheses

6x-6+3

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

-6x-6x+3+15=0

We add all the numbers together, and all the variables

-12x+18=0

We move all terms containing x to the left, all other terms to the right

-12x=-18

x=-18/-12

x=1+1/2

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