-3(2x-5)=6(x-4)+9

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Solution for -3(2x-5)=6(x-4)+9 equation: 



-3(2x-5)=6(x-4)+9

We move all terms to the left:

-3(2x-5)-(6(x-4)+9)=0

We multiply parentheses

-6x-(6(x-4)+9)+15=0



We calculate terms in parentheses: -(6(x-4)+9), so:

6(x-4)+9

We multiply parentheses

6x-24+9

We add all the numbers together, and all the variables

6x-15

Back to the equation:

-(6x-15)



We get rid of parentheses

-6x-6x+15+15=0

We add all the numbers together, and all the variables

-12x+30=0

We move all terms containing x to the left, all other terms to the right

-12x=-30

x=-30/-12

x=2+1/2

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