-3(2x-8)10x=16

Solution for -3(2x-8)10x=16 equation:

-3(2x-8)10x=16

We move all terms to the left:

-3(2x-8)10x-(16)=0

We multiply parentheses

-60x^2+240x-16=0

a = -60; b = 240; c = -16;
Δ = b2-4ac
Δ = 2402-4·(-60)·(-16)
Δ = 53760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{53760}=\sqrt{256*210}=\sqrt{256}*\sqrt{210}=16\sqrt{210}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-16\sqrt{210}}{2*-60}=\frac{-240-16\sqrt{210}}{-120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+16\sqrt{210}}{2*-60}=\frac{-240+16\sqrt{210}}{-120}
$