-3(2y+2)+y=8

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Solution for -3(2y+2)+y=8 equation: 



-3(2y+2)+y=8

We move all terms to the left:

-3(2y+2)+y-(8)=0

We add all the numbers together, and all the variables

y-3(2y+2)-8=0

We multiply parentheses

y-6y-6-8=0

We add all the numbers together, and all the variables

-5y-14=0

We move all terms containing y to the left, all other terms to the right

-5y=14

y=14/-5

y=-2+4/5

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