-3(2y+2)-8=-4(y+5)+2y

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Solution for -3(2y+2)-8=-4(y+5)+2y equation: 



-3(2y+2)-8=-4(y+5)+2y

We move all terms to the left:

-3(2y+2)-8-(-4(y+5)+2y)=0

We multiply parentheses

-6y-(-4(y+5)+2y)-6-8=0



We calculate terms in parentheses: -(-4(y+5)+2y), so:

-4(y+5)+2y

We add all the numbers together, and all the variables

2y-4(y+5)

We multiply parentheses

2y-4y-20

We add all the numbers together, and all the variables

-2y-20

Back to the equation:

-(-2y-20)



We add all the numbers together, and all the variables

-6y-(-2y-20)-14=0

We get rid of parentheses

-6y+2y+20-14=0

We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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