-3(2y-2)-y=-4(y-3)

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Solution for -3(2y-2)-y=-4(y-3) equation: 



-3(2y-2)-y=-4(y-3)

We move all terms to the left:

-3(2y-2)-y-(-4(y-3))=0

We add all the numbers together, and all the variables

-1y-3(2y-2)-(-4(y-3))=0

We multiply parentheses

-1y-6y-(-4(y-3))+6=0



We calculate terms in parentheses: -(-4(y-3)), so:

-4(y-3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)



We add all the numbers together, and all the variables

-7y-(-4y+12)+6=0

We get rid of parentheses

-7y+4y-12+6=0

We add all the numbers together, and all the variables

-3y-6=0

We move all terms containing y to the left, all other terms to the right

-3y=6

y=6/-3

y=-2

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