-3(2y-2)=2(3y+9)

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Solution for -3(2y-2)=2(3y+9) equation: 



-3(2y-2)=2(3y+9)

We move all terms to the left:

-3(2y-2)-(2(3y+9))=0

We multiply parentheses

-6y-(2(3y+9))+6=0



We calculate terms in parentheses: -(2(3y+9)), so:

2(3y+9)

We multiply parentheses

6y+18

Back to the equation:

-(6y+18)



We get rid of parentheses

-6y-6y-18+6=0

We add all the numbers together, and all the variables

-12y-12=0

We move all terms containing y to the left, all other terms to the right

-12y=12

y=12/-12

y=-1

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