-3(2y-3)+8y=7+3(6y-4)

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Solution for -3(2y-3)+8y=7+3(6y-4) equation: 



-3(2y-3)+8y=7+3(6y-4)

We move all terms to the left:

-3(2y-3)+8y-(7+3(6y-4))=0

We add all the numbers together, and all the variables

8y-3(2y-3)-(7+3(6y-4))=0

We multiply parentheses

8y-6y-(7+3(6y-4))+9=0



We calculate terms in parentheses: -(7+3(6y-4)), so:

7+3(6y-4)

determiningTheFunctionDomain
3(6y-4)+7

We multiply parentheses

18y-12+7

We add all the numbers together, and all the variables

18y-5

Back to the equation:

-(18y-5)



We add all the numbers together, and all the variables

2y-(18y-5)+9=0

We get rid of parentheses

2y-18y+5+9=0

We add all the numbers together, and all the variables

-16y+14=0

We move all terms containing y to the left, all other terms to the right

-16y=-14

y=-14/-16

y=7/8

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