-3(2y-3)=3(2-3y)-3

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Solution for -3(2y-3)=3(2-3y)-3 equation:



-3(2y-3)=3(2-3y)-3
We move all terms to the left:
-3(2y-3)-(3(2-3y)-3)=0
We add all the numbers together, and all the variables
-3(2y-3)-(3(-3y+2)-3)=0
We multiply parentheses
-6y-(3(-3y+2)-3)+9=0
We calculate terms in parentheses: -(3(-3y+2)-3), so:
3(-3y+2)-3
We multiply parentheses
-9y+6-3
We add all the numbers together, and all the variables
-9y+3
Back to the equation:
-(-9y+3)
We get rid of parentheses
-6y+9y-3+9=0
We add all the numbers together, and all the variables
3y+6=0
We move all terms containing y to the left, all other terms to the right
3y=-6
y=-6/3
y=-2

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