-3(2y-4)+3y=3(y+7)

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Solution for -3(2y-4)+3y=3(y+7) equation: 



-3(2y-4)+3y=3(y+7)

We move all terms to the left:

-3(2y-4)+3y-(3(y+7))=0

We add all the numbers together, and all the variables

3y-3(2y-4)-(3(y+7))=0

We multiply parentheses

3y-6y-(3(y+7))+12=0



We calculate terms in parentheses: -(3(y+7)), so:

3(y+7)

We multiply parentheses

3y+21

Back to the equation:

-(3y+21)



We add all the numbers together, and all the variables

-3y-(3y+21)+12=0

We get rid of parentheses

-3y-3y-21+12=0

We add all the numbers together, and all the variables

-6y-9=0

We move all terms containing y to the left, all other terms to the right

-6y=9

y=9/-6

y=-1+1/2

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