-3(2y-4)=-4y+20

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Solution for -3(2y-4)=-4y+20 equation: 



-3(2y-4)=-4y+20

We move all terms to the left:

-3(2y-4)-(-4y+20)=0

We multiply parentheses

-6y-(-4y+20)+12=0

We get rid of parentheses

-6y+4y-20+12=0

We add all the numbers together, and all the variables

-2y-8=0

We move all terms containing y to the left, all other terms to the right

-2y=8

y=8/-2

y=-4

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