-3(2y-5)-y=-4(y-5)

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Solution for -3(2y-5)-y=-4(y-5) equation: 



-3(2y-5)-y=-4(y-5)

We move all terms to the left:

-3(2y-5)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-3(2y-5)-(-4(y-5))=0

We multiply parentheses

-1y-6y-(-4(y-5))+15=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-7y-(-4y+20)+15=0

We get rid of parentheses

-7y+4y-20+15=0

We add all the numbers together, and all the variables

-3y-5=0

We move all terms containing y to the left, all other terms to the right

-3y=5

y=5/-3

y=-1+2/3

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