-3(2y-8)+10y=16

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Solution for -3(2y-8)+10y=16 equation: 



-3(2y-8)+10y=16

We move all terms to the left:

-3(2y-8)+10y-(16)=0

We add all the numbers together, and all the variables

10y-3(2y-8)-16=0

We multiply parentheses

10y-6y+24-16=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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