-3(2y-8)-y=3(y-5)

Solution for -3(2y-8)-y=3(y-5) equation:

-3(2y-8)-y=3(y-5)

We move all terms to the left:

-3(2y-8)-y-(3(y-5))=0

We add all the numbers together, and all the variables

-1y-3(2y-8)-(3(y-5))=0

We multiply parentheses

-1y-6y-(3(y-5))+24=0


We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)


We add all the numbers together, and all the variables

-7y-(3y-15)+24=0

We get rid of parentheses

-7y-3y+15+24=0

We add all the numbers together, and all the variables

-10y+39=0

We move all terms containing y to the left, all other terms to the right

-10y=-39

y=-39/-10

y=3+9/10