-3(3+2n)=2(n+3)+1

Solution for -3(3+2n)=2(n+3)+1 equation:

-3(3+2n)=2(n+3)+1

We move all terms to the left:

-3(3+2n)-(2(n+3)+1)=0

We add all the numbers together, and all the variables

-3(2n+3)-(2(n+3)+1)=0

We multiply parentheses

-6n-(2(n+3)+1)-9=0


We calculate terms in parentheses: -(2(n+3)+1), so:

2(n+3)+1

We multiply parentheses

2n+6+1

We add all the numbers together, and all the variables

2n+7

Back to the equation:

-(2n+7)


We get rid of parentheses

-6n-2n-7-9=0

We add all the numbers together, and all the variables

-8n-16=0

We move all terms containing n to the left, all other terms to the right

-8n=16

n=16/-8

n=-2