-3(3b+1)+(10b-3)=0

Solution for -3(3b+1)+(10b-3)=0 equation:

Simplifying
-3(3b + 1) + (10b + -3) = 0

Reorder the terms:
-3(1 + 3b) + (10b + -3) = 0
(1 * -3 + 3b * -3) + (10b + -3) = 0
(-3 + -9b) + (10b + -3) = 0

Reorder the terms:
-3 + -9b + (-3 + 10b) = 0

Remove parenthesis around (-3 + 10b)
-3 + -9b + -3 + 10b = 0

Reorder the terms:
-3 + -3 + -9b + 10b = 0

Combine like terms: -3 + -3 = -6
-6 + -9b + 10b = 0

Combine like terms: -9b + 10b = 1b
-6 + 1b = 0

Solving
-6 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 1b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 1b = 0 + 6
1b = 0 + 6

Combine like terms: 0 + 6 = 6
1b = 6

Divide each side by '1'.
b = 6

Simplifying
b = 6