-3(3b+2)+(10b-4)=0

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Solution for -3(3b+2)+(10b-4)=0 equation:


Simplifying
-3(3b + 2) + (10b + -4) = 0

Reorder the terms:
-3(2 + 3b) + (10b + -4) = 0
(2 * -3 + 3b * -3) + (10b + -4) = 0
(-6 + -9b) + (10b + -4) = 0

Reorder the terms:
-6 + -9b + (-4 + 10b) = 0

Remove parenthesis around (-4 + 10b)
-6 + -9b + -4 + 10b = 0

Reorder the terms:
-6 + -4 + -9b + 10b = 0

Combine like terms: -6 + -4 = -10
-10 + -9b + 10b = 0

Combine like terms: -9b + 10b = 1b
-10 + 1b = 0

Solving
-10 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = 0 + 10
1b = 0 + 10

Combine like terms: 0 + 10 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10

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