-3(3b+4)=(10b-8)=0

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Solution for -3(3b+4)=(10b-8)=0 equation: 



-3(3b+4)=(10b-8)=0

We move all terms to the left:

-3(3b+4)-((10b-8))=0

We multiply parentheses

-9b-((10b-8))-12=0



We calculate terms in parentheses: -((10b-8)), so:

(10b-8)

We get rid of parentheses

10b-8

Back to the equation:

-(10b-8)



We get rid of parentheses

-9b-10b+8-12=0

We add all the numbers together, and all the variables

-19b-4=0

We move all terms containing b to the left, all other terms to the right

-19b=4

b=4/-19

b=-4/19

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