-3(3b+5)=b-25

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Solution for -3(3b+5)=b-25 equation: 



-3(3b+5)=b-25

We move all terms to the left:

-3(3b+5)-(b-25)=0

We multiply parentheses

-9b-(b-25)-15=0

We get rid of parentheses

-9b-b+25-15=0

We add all the numbers together, and all the variables

-10b+10=0

We move all terms containing b to the left, all other terms to the right

-10b=-10

b=-10/-10

b=1

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