-3(3d+10)+6(2d-3)=-36

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Solution for -3(3d+10)+6(2d-3)=-36 equation: 



-3(3d+10)+6(2d-3)=-36

We move all terms to the left:

-3(3d+10)+6(2d-3)-(-36)=0

We add all the numbers together, and all the variables

-3(3d+10)+6(2d-3)+36=0

We multiply parentheses

-9d+12d-30-18+36=0

We add all the numbers together, and all the variables

3d-12=0

We move all terms containing d to the left, all other terms to the right

3d=12

d=12/3

d=4

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