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-3(3r+5)=2(10-r)
We move all terms to the left:
-3(3r+5)-(2(10-r))=0
We add all the numbers together, and all the variables
-3(3r+5)-(2(-1r+10))=0
We multiply parentheses
-9r-(2(-1r+10))-15=0
We calculate terms in parentheses: -(2(-1r+10)), so:We get rid of parentheses
2(-1r+10)
We multiply parentheses
-2r+20
Back to the equation:
-(-2r+20)
-9r+2r-20-15=0
We add all the numbers together, and all the variables
-7r-35=0
We move all terms containing r to the left, all other terms to the right
-7r=35
r=35/-7
r=-5
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