-3(3u-6)+6u=3(u+3)

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Solution for -3(3u-6)+6u=3(u+3) equation: 



-3(3u-6)+6u=3(u+3)

We move all terms to the left:

-3(3u-6)+6u-(3(u+3))=0

We add all the numbers together, and all the variables

6u-3(3u-6)-(3(u+3))=0

We multiply parentheses

6u-9u-(3(u+3))+18=0



We calculate terms in parentheses: -(3(u+3)), so:

3(u+3)

We multiply parentheses

3u+9

Back to the equation:

-(3u+9)



We add all the numbers together, and all the variables

-3u-(3u+9)+18=0

We get rid of parentheses

-3u-3u-9+18=0

We add all the numbers together, and all the variables

-6u+9=0

We move all terms containing u to the left, all other terms to the right

-6u=-9

u=-9/-6

u=1+1/2

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