-3(3v-9)+3v=6(v+2)

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Solution for -3(3v-9)+3v=6(v+2) equation: 



-3(3v-9)+3v=6(v+2)

We move all terms to the left:

-3(3v-9)+3v-(6(v+2))=0

We add all the numbers together, and all the variables

3v-3(3v-9)-(6(v+2))=0

We multiply parentheses

3v-9v-(6(v+2))+27=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

-6v-(6v+12)+27=0

We get rid of parentheses

-6v-6v-12+27=0

We add all the numbers together, and all the variables

-12v+15=0

We move all terms containing v to the left, all other terms to the right

-12v=-15

v=-15/-12

v=1+1/4

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