-3(3x+-4=16x-26x+4+8

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Solution for -3(3x+-4=16x-26x+4+8 equation: 



-3(3x+-4=16x-26x+4+8

We move all terms to the left:

-3(3x+-4-(16x-26x+4+8)=0

We add all the numbers together, and all the variables

-3(3x+-4-(-10x+12)=0

We use the square of the difference formula

-3(3x-4-(-10x+12)=0

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