-3(3x+1)+14=3(7x-3)-10

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Solution for -3(3x+1)+14=3(7x-3)-10 equation: 



-3(3x+1)+14=3(7x-3)-10

We move all terms to the left:

-3(3x+1)+14-(3(7x-3)-10)=0

We multiply parentheses

-9x-(3(7x-3)-10)-3+14=0



We calculate terms in parentheses: -(3(7x-3)-10), so:

3(7x-3)-10

We multiply parentheses

21x-9-10

We add all the numbers together, and all the variables

21x-19

Back to the equation:

-(21x-19)



We add all the numbers together, and all the variables

-9x-(21x-19)+11=0

We get rid of parentheses

-9x-21x+19+11=0

We add all the numbers together, and all the variables

-30x+30=0

We move all terms containing x to the left, all other terms to the right

-30x=-30

x=-30/-30

x=1

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