-3(3x+4)+6+2(3x+2)=4(x+1)

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Solution for -3(3x+4)+6+2(3x+2)=4(x+1) equation: 



-3(3x+4)+6+2(3x+2)=4(x+1)

We move all terms to the left:

-3(3x+4)+6+2(3x+2)-(4(x+1))=0

We multiply parentheses

-9x+6x-(4(x+1))-12+4+6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

-3x-(4x+4)-2=0

We get rid of parentheses

-3x-4x-4-2=0

We add all the numbers together, and all the variables

-7x-6=0

We move all terms containing x to the left, all other terms to the right

-7x=6

x=6/-7

x=-6/7

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