-3(3x-2)+6x=4+4(3x-2)

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Solution for -3(3x-2)+6x=4+4(3x-2) equation: 



-3(3x-2)+6x=4+4(3x-2)

We move all terms to the left:

-3(3x-2)+6x-(4+4(3x-2))=0

We add all the numbers together, and all the variables

6x-3(3x-2)-(4+4(3x-2))=0

We multiply parentheses

6x-9x-(4+4(3x-2))+6=0



We calculate terms in parentheses: -(4+4(3x-2)), so:

4+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+4

We multiply parentheses

12x-8+4

We add all the numbers together, and all the variables

12x-4

Back to the equation:

-(12x-4)



We add all the numbers together, and all the variables

-3x-(12x-4)+6=0

We get rid of parentheses

-3x-12x+4+6=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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