-3(3x-4)=2x+23

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Solution for -3(3x-4)=2x+23 equation: 



-3(3x-4)=2x+23

We move all terms to the left:

-3(3x-4)-(2x+23)=0

We multiply parentheses

-9x-(2x+23)+12=0

We get rid of parentheses

-9x-2x-23+12=0

We add all the numbers together, and all the variables

-11x-11=0

We move all terms containing x to the left, all other terms to the right

-11x=11

x=11/-11

x=-1

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